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  • #5738
    Richard Schneider
    Participant

    I have small dam 150′ crest length and 110 acre feet impoundment. 100 yr. = 3200 cfs.
    I model the breach for 5 min failure at the time of 100 yr. peak at the dam. Breach method is overtopping. I get same flow above and below the dam i.e. 100 yr. no breach. Tried exaggerated breach dimensions–same result. ?????

    #9183
    Anonymous
    Guest

    The average flow for 110 ac-ft over a 5 minute breach is only 1,600 cfs. It may be the timing of the peak inflow versus peak outflow for the breach is sufficiently different that the flow comes out the same. There will be some attenuation of the peak flow in the reservoir depending on the time of the peak inflow versus the start of the breach since you are failing the dam due to overtopping.

    #9184
    Richard Schneider
    Participant

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    From: “Richard H. Schneider”
    To: “John [via HEC-RAS Help]”
    Subject: RE: Dam Breach
    Thread-Topic: Dam Breach
    Thread-Index: AQHQXesMrbo4EQ1kTUm8s2r5CqBx8Z0b8suQ
    Date: Sat, 14 Mar 2015 13:05:20 +0000
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    Thanks John-I thought of that after I posted the message. I played with tim=
    ing and got it to work.
    Have a nice week!

    Dick Schneider, P.E.
    Project Manager
    KAPUR & ASSOCIATES, INC.
    10101 Market Street, Ste C20, Rothschild, Wisconsin 54474
    main 715-359-9668 Ext. 4005 | fax 715-359-4844 | cell 715-573-1269
    http://www.kapurengineers.com<http://www.kapurengineers.com/>

    From: John [via HEC-RAS Help] [mailto:[email protected]=
    m]
    Sent: Friday, March 13, 2015 7:09 PM
    To: Richard H. Schneider
    Subject: Re: Dam Breach

    The average flow for 110 ac-ft over a 5 minute breach is only 1,600 cfs. I=
    t may be the timing of the peak inflow versus peak outflow for the breach i=
    s sufficiently different that the flow comes out the same. There will be s=
    ome attenuation of the peak flow in the reservoir depending on the time of =
    the peak inflow versus the start of the breach since you are failing the da=
    m due to overtopping.
    ________________________________
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    Thanks John-I thought of that after I post=
    ed the message. I played with timing and got it to work.
    <= /p>

    Have a nice week!

     

    Dick Schneider, P.E.

    Project Manager

    KAPUR & ASSOCIATES, =
    INC.

    10101 Market Street, Ste C20, Rothschild, =
    Wisconsin 54474

    main 715-359-9668 Ext. 4005 | f=
    ax 715-359-4844 | cell 715-573-1269

    <= span style=3D"color:#1F497D">http://www.kapurengineers.com

     

    From: John [vi=
    a HEC-RAS Help] [mailto:ml-node+[email protected]]

    Sent: Friday, March 13, 2015 7:09 PM
    To: Richard H. Schneider
    Subject: Re: Dam Breach

     

    Th=
    e average flow for 110 ac-ft over a 5 minute breach is only 1,600 cfs. &nbs=
    p;It may be the timing of the peak inflow versus peak outflow for the breac=
    h is sufficiently different that the flow
    comes out the same.  There will be some attenuation of the peak flow =
    in the reservoir depending on the time of the peak inflow versus the start =
    of the breach since you are failing the dam due to overtopping.


    If you reply to this email, your message will be added to the discussi=
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    tml

    To unsubscribe from Dam Breach,

    click here
    .
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